Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops.

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#### Solution

Let CD and AB be the poles of height 11 m and 6 m.

Therefore, CP = 11 − 6 = 5 m

From the figure, it can be observed that AP = 12m

Applying Pythagoras theorem for ΔAPC, we obtain

AP^{2} + PC^{2} = AC^{2}

(12 m)^{2} + (5m)^{2} = (AC)^{2}

AC^{2} = (144 + 25)m^{2} = 169 m^{2}

AC = 13m

Therefore, the distance between their tops is 13 m.

Concept: Right-angled Triangles and Pythagoras Property

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